White phosphorus is a tetra atomic solid `[P_(4)(s)]` at room temperature and on strong heating in absence of oxyge, it polymerizes into red phosphorus as:
`/_\H=-104kJ//"mol"` of `P_(4)`
The enthalpy of sublimation `[P_(4)(s)toP_(4)(g)]` white is `59KJ//"mol"` and enthalpy of atomization is `1265 KJ//"mol"` of `P(g)`
The `P-P` bond enthalpy in red phosphorus joining the two tetrahedral is:

Options

A. `201KJ`
B. `104KJ`
C. `305KJ`
D. `80KJ`

Answer

C

Explanation

c
On an average one `P-P` bond of tetrahedral is broken and one new `P-P` bond joining the two tetrahedral units is formed.
`201-x=-104`
`:.x=305KJ"mol"^(-1)`