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Let f(x)=ax^(4)+bx^(2)+3x+7 and f(-4)=22...

Let `f(x)=ax^(4)+bx^(2)+3x+7` and `f(-4)=2286` and `f=(4)=N`. The number of ways in which `N` can be resolved as a product of two divisors which are relatively prime:

A

15

B

16

C

17

D

none of these

Text Solution

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The correct Answer is:
B

b
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