`60ml` of mixture of equal volumes of `Cl_(2)` and an oxide of chloine, i.e., `Cl_(2)O_(n)` was heated and then cooled back to the original temperature. The resulting gas mixture was found to have volume of `75ml`. On treatment with `KOH` solution, the volume contracted to `15ml`. Assume that all measurements are made at the same temperature and pressure. Deduce the value of `n` in `Cl_(2)O_(n)`. The oxide of `Cl_(2)` n heating decomposes quantiatively to `O_(2)` and `Cl_(2)`.

Answer

1

Explanation

`underset(0) underset(30)(Cl_(2))+underset(0)underset(30)(CL_(2))O_(n)to underset(60)underset(0)(2Cl_(2))+n/2 underset(15n)underset(0)(O_(2))`
`KOH` absorbs `Cl_(2)`
So, `15n=15`
`n=1`