By passing a certain amount of charge through `NaCl` solution, `9.2` lit of `Cl_(2)` were liberated at STP. When the same charge is passed through a nitrate solution of metal `M` i.e. `M(NO_(3))x 7.467` gm of the metal was deposited . If the specific heat of metal is `0.16cal//gm`, what is the value of `x` (`x` is integer).

Answer

4

Explanation

Specific heat `xx` At.Wt. `=6.4`
Atomic weight `=29.63`
Eq. of metal `=` Eq. of `Cl_(2)`
`(7.467xx x)/29.63=(71xx9.2)/(22.4xx35.5)`
`x=3.25`
`x=3` (`x` is an integer)