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Consider the lines, L(1):x/2=y/(-3)=z/1 ...

Consider the lines, `L_(1):x/2=y/(-3)=z/1` and `L_(3):(x-2)/3=(y-1)/(-5)=(z+2)/2`, then the line along shortest distance can be, costituted by the line of intersection of planes

A

`4x+y-5z=0`

B

`x-3y+5z=0`

C

`5x-7y+2z=-1`

D

`7x+y-8z=31`

Text Solution

Verified by Experts

The correct Answer is:
A, D
`|(x,y,z),(2,-3,1),(1,1,1)|=0,|(x-2, y-1, z+2),(3, -5, 2),(1, 1, 1)|=0`
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