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Taking one mole of N(2(g)) and excess of...

Taking one mole of `N_(2(g))` and excess of `H_(2)(g)`, under suitable conditions, formation of `NH_(3)` is completed when `NH_(3)(g)` has mole fraction of `0.5`, The initial moles of `H_(2)` are?

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The correct Answer is:
5

`underset (0) underset (1) (N_(2))+ underset(a-3) underset(a) (3H_(2))tounderset(2) underset(0) (2NH_(3))`
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