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The rate of disintegration of a certain ...

The rate of disintegration of a certain radioactive sample at any instant is `8100` dpm. Fifty minutes later the rate becomes `2700` dpm. The half of the radioactive sample will be (Take `log2=0.3, log3=0.5, log5=0.7`)

A

30 minutes

B

61 minutes

C

`47.8` minutes

D

`33.3` minutes

Text Solution

Verified by Experts

The correct Answer is:
A
`r_(1)=lamdaN_(1)`
`8100=lamdaN_(@)`
`2700=lamdaN_(t)`
`lamda=(2.303)/50 "log" (N_(@))/(N_(t))=(0.693)/(t_(1//2))`
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