Which of the following trend is/are correct?

Options

A. `CIO_(2)gtSO_(2)gtCO_(2)gtP_(2)O_(5)` (acidic nature)
B. `NagtSigtAlgtMg`(second I.P.)
C. `SgtSegtTegtO`(electron affinity)
D. `H_(3)PO_(2)gtH_(3)PO_(3)gtH_(3)PO_(4)(Ka_(1))`

Answer

C, D

Explanation

`Cl` is most electronegative among `Cl, S,P` & `C` so `ClO_(2)` is most acidic and `Ea` of `O` is least in its `gp`, `H-underset(1) underset(H) underset(|) overset(O) overset(||)(P)-O^(-), H-O-underset(2) underset(H) underset(|)overset (O) overset(||)(P)-O^(-)`
Due to cross conjugation in (2), 1 is weaker base than 2 so `H_(3)PO_(2)` is stronger acid than `H_(3)PO_(3)`, similarly relate `H_(3)PO_(4)` for option (b) refer `e^(-)` configuration & `ENCimpliesNagtAlgtSigtMg`.