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If `theta` is acute angle of intersect between two curves `x^(2)+5y^(2)=6` and `y^(2)=x`, then `cot theta` is equal to

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`:'x^(2)+5x-6=0`
`implies (x-1)(x+6)=0impliesx=1`
`:. x+5y=6`…..(i) tangents
& `y=1/2(x+1)`………..(ii)
`:.tantheta =|(-1/5+1/2)/(1+1/10)|=3/11`
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