`60ml` of `0.1M NH_(4)OH` is mixed with `40 ml` of `0.1M HCl`. Which of the following statement(s) is/are INCORRECT about the resulting soution/mixture? (Given `pK_(b)(NH_(4)OH)=4.74,log2=0.3`)

Options

A. The `pH` of the resulting solution is 5.04
B. The resulting solution is a basic buffer.
C. The `pOH` of the resulting solution is 9.26
D. The resulting solution is acidic due to hydrolysis of `NH_(4)Cl`

Answer

A, C, D

Explanation

`underset(2) underset(60xx0.1=6)(NH_(4)OH)+underset(0) underset(40xx0.1=4)(HCl)tounderset(4) underset(0)(NH_(4)Cl)+H_(2)O`
The resulting solution is a basic buffer
`pOH=pK_(b)+ "log"([NH_(4)^(+)])/([NH_(4)OH])`
`pOH=4.74+"log" 4/2=5.04`
`pH=14-5.04=8.96`