`6ml` of `0.1M CH_(3)COOH` when mixed with `x` ml of `0.1 M NaOH` the `pH` of the resulting buffer solution was found to be `5.04`. The value of `x` is `(log2=0.3)pK_(a(CH_(3)COOH))=4.74`

Answer

4

Explanation

`underset(0.6-0.x) underset(6xx0.1=0.6)(CH_(3)COOH)+underset(x xx 0.1)(NaOH)tounderset(0.x)underset(0)(CH_(3)COONa)+H_(2)O`
The resulting solution is a buffer solution.
`pH=pK_(a)= "log"([CH_(3)COO^(-)])/([CH_(3)COOH]) 0.3 = "log" (0.x)/(0.-0.x)`
`pH=pK_(a)+"log"(0.x)/(0.6-0.x) log 2="log" (0.x)/(0.6-0.x)`
`5.04=4.74+"log"(0.x)/(0.6-0.x) (0.x)/(0.6-0.x)=2`
`x=4`