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How many of the following hydroxides are...

How many of the following hydroxides are soluble in excess `NaOH` solution?
`Fe(OH)_(3), Al(OH)_(3),Zn(OH)_(3),Zn(OH)_(2), Ni(OH)_(2),Mn(OH)_(2), Sn(OH)_(2), Sn(OH)_(2), Cu(OH)_(2)`

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To determine how many of the given hydroxides are soluble in excess NaOH solution, we will analyze each hydroxide one by one. The hydroxides given are: 1. Fe(OH)₃ 2. Al(OH)₃ 3. Zn(OH)₃ 4. Zn(OH)₂ 5. Ni(OH)₂ 6. Mn(OH)₂ 7. Sn(OH)₂ 8. Cu(OH)₂ ### Step-by-step solution: 1. **Fe(OH)₃ (Iron(III) hydroxide)**: - Iron(III) hydroxide is generally insoluble in excess NaOH. - **Conclusion**: Not soluble. 2. **Al(OH)₃ (Aluminum hydroxide)**: - Aluminum hydroxide is amphoteric and reacts with excess NaOH to form sodium aluminate (NaAlO₂), which is soluble. - **Conclusion**: Soluble. 3. **Zn(OH)₃ (Zinc(III) hydroxide)**: - Zinc(III) hydroxide is not commonly referenced; however, zinc hydroxide (Zn(OH)₂) is amphoteric and can dissolve in excess NaOH to form sodium zincate (Na₂ZnO₂). - **Conclusion**: Not applicable as Zn(OH)₃ is not a common species; we will consider Zn(OH)₂ instead. 4. **Zn(OH)₂ (Zinc(II) hydroxide)**: - Zinc(II) hydroxide is amphoteric and reacts with excess NaOH to form sodium zincate (Na₂ZnO₂), which is soluble. - **Conclusion**: Soluble. 5. **Ni(OH)₂ (Nickel(II) hydroxide)**: - Nickel(II) hydroxide is generally insoluble in excess NaOH. - **Conclusion**: Not soluble. 6. **Mn(OH)₂ (Manganese(II) hydroxide)**: - Manganese(II) hydroxide is generally insoluble in excess NaOH. - **Conclusion**: Not soluble. 7. **Sn(OH)₂ (Tin(II) hydroxide)**: - Tin(II) hydroxide is amphoteric and reacts with excess NaOH to form sodium stannate (Na₂SnO₂), which is soluble. - **Conclusion**: Soluble. 8. **Cu(OH)₂ (Copper(II) hydroxide)**: - Copper(II) hydroxide is generally insoluble in excess NaOH. - **Conclusion**: Not soluble. ### Summary of Solubility: - Soluble in excess NaOH: Al(OH)₃, Zn(OH)₂, Sn(OH)₂ - Not soluble in excess NaOH: Fe(OH)₃, Zn(OH)₃ (not applicable), Ni(OH)₂, Mn(OH)₂, Cu(OH)₂ ### Final Count: Out of the given hydroxides, **3 hydroxides (Al(OH)₃, Zn(OH)₂, Sn(OH)₂)** are soluble in excess NaOH.

To determine how many of the given hydroxides are soluble in excess NaOH solution, we will analyze each hydroxide one by one. The hydroxides given are: 1. Fe(OH)₃ 2. Al(OH)₃ 3. Zn(OH)₃ 4. Zn(OH)₂ 5. Ni(OH)₂ ...
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