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4 mole of Sl(2)Cl(4)(g) is introduced in...

4 mole of `Sl_(2)Cl_(4)(g)` is introduced innto a `10L` vessel. The following equilibrium was established `S_(2)Cl_(4)(g)hArr2SCl_(2)(g)`
at equilibrium `0.2` mol of `S_(2)Cl_(4)` was present in the vessel. The value of equilibrium constant is.

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The correct Answer is:
`28.88`
`S_(2)Cl(g)hArr2SCl_(2)(g)`
Initial 4 0
At equilibrium 0.2 7.6
`:. [S_(2)Cl_(4)]=0.2/10 [SC_(2)]=7.6/10`
`K_(c)=([SCl_(2)]^(2))/([S_(2)Cl_(4)])`
`(7.6/10xx7.6/10)/(0.2/10)`
`=28.88`
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