In the reaction
`2x+B_(2)H_(6)to [BH_(2)(x)_(2)]^(+)[BH_(4)]^(-)`
The reagents (s) `'x'` is (are):

Options

A. `NH_(3)`
B. `CH_(3)NH_(2)`
C. `(CH_(3))_(2)NH`
D. `(CH)_(3)N`

Answer

A, B, C

Explanation

`H_(3)N.+B_(2)H_(6)to[H_(3)NtoBH_(2)larrNH_(3)]^(+)[BH_(4)]^(-)`
`CH_(3)NH_(2):+B_(2)H_(6)to[CH_(3)NH_(2)toBH_(2)larrNH_(2)CH_(3)]^(+)[BH_(4)]^(-)`
`(CH_(3))NH+B_(2)H_(6)to[(CH_(3))_(2)NHto BH_(2)larrNH(CH_(3))_(2)]^(+)[BH_(4)]^(-)`