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The number of solutions in the interval ...

The number of solutions in the interval `[0, pi]` of the equation `sin^(3)x cos 3x+sin 3xcos^(3)x=0` is equal to

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The correct Answer is:
5
Use `sin^(3)x=(3sinx-sin3x)/4` and `cos^(3) x=(3cosx+cos3x)/4`
Equation becomes `sin4x=0`
`x=(npi)/4`
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