A sample of `1.0` gm of organic compound was treated with `NaOH` and `NH_(3)` evolved was absorbed in `70ml 0.5M H_(2)SO_(4)`. The residual acid required `65 ml` of `0.5MNaOH` solution of neutraization in Kjeldahl's method. What is the percentage of nitrogen is organic compound.

Answer

`00063.75`

Explanation

Mili moles of `H_(2)SO_(4)` initially `=70xx0.5=35`
Mili moles of `NaOH` required `=65xx0.5=32.5`
`:.` Mili moles of `H_(2)SO_(4)` consumed `=35-(32.5//2)`
`=18.75`
`:.` Mili moles `NH_(3)=37.5`
`:.W_(NH_(3))=(37.5xx17)/1000=0.6375` gm
`% NH_(3)=(0.6375)/1.0xx100=63.75`