A particle moves with simple harmonic motion in a straight line. In first `taus`, after starting form rest it travels a destance a, and in next `tau s` it travels 2a, in same direction, then:

A particle moves with a simple harmonic motion in a straight line, in the first second starting from rest it travels a distance a and in the next second it travels a distance b in the same direction. The amplitude of the motion is

A particle moves with a simple harmonic motion in a straight line, in the first second starting from rest it travels a distance a and in the next second it travels a distance b in the same direction. The amplitude of the motion is

A particle moves simple harmonically in a straight line starting from rest. In first 't' sec it travels a distance 'a' and in next 't'sec it travels '2a' in same direction. Then its time period is ?

A particle performs SHM in a straight line. In the first second, starting from rest, it travels a distance a and in the next second it travels a distance b in the same direction. The amplitude of the SHM is

A particle performs SHM in a straight line. In the first second, starting from rest, it travels a distance a and in the next second it travels a distance b in the same direction. The amplitude of the SHM is

A particle moves with SHM in a straight liine. In the first second afer starting from rest, it travels a distance x_(1) cm and in the next second it travels a distance x_(2) cm in the same direction. Prove that the amplitude of oscillation is 2x_(1)^(2)//(3x_(1)-x_(2)) .

A particle performs SHM in a straight line. In the first second, starting from rest, it travels a distance a and in the next second it travels a distance b in the same side of mean position. The amplitude of the SHM is