Initial volume of `H_(2)` gas saturated with water vapour is confined under a piston in a container is 10 litres as shown in the given figure.

the container also contains some liquid water. The total pressure over liquid water is `80cm` of `Hg`. If now the piston is removed such that volume of container is doubled, then final total pressure over liqid water in the container is `P`. The vapour pressure of water is `20cm` of `Hg` and volume of liquid is negligible. Calculate `P//10`.........

Answer

5

Explanation

`P_(1)V_(1)=P_(2)V_(2)`
`P_(2)=` Pressure of `H_(2)` gas `=(60xx10)/20`
`P_(2)=30cm` of `Hg`
Final total pressure over liquid water `(P)=30+20=50 cm` of `Hg`
`P/10=50/10=5`