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Let AB be a chord of the parabola x^(2) ...

Let AB be a chord of the parabola `x^(2) = 4y`. A circle drawn with AB as diameter passes through the vertex C of the parabola. If area of `DeltaABC = 20 sq`. units then the coordinates of A can be

A

`(6,9)`

B

`(-6,9)`

C

`(-8,16)`

D

`(8,16)`

Text Solution

Verified by Experts

The correct Answer is:
C, D
`A(2t_(1),t_(1).^(2))B(2t_(2),t_(2).^(2))`
`t_(1)t_(2) = - 4`
Area `|(2t_(1),t_(1).^(2),1),(2t_(2),t_(2).^(2),1),(0,0,1)|=20`
solving `t_(1)=pm4,pm1`
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