Prussian blue is formed when

Options

A. Ferrous sulphate reacts with `FeCI_(3)`
B. Ferric sulphate reacts with `K_(4)[Fe(CN)_(6)]`
C. Ferrous ammonium sulphate reacts with `FeCI_(3)`
D. Ammonium sulphate reacts with `FeCI_(3)`

Answer

B

Explanation

`Fe(SO_(4))_(3)(rarr)2Fe^(3+)+3SO_(4)^(2-)`
`K_(4)[(Fe(CN))_(6)]+2Fe^(3+)(rarr)Fe_(4)underset("Prusion blue")[(Fe(CN)_(6)]_(3)`