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Calculate the percentage of SN^(-1) prod...

Calculate the percentage of `SN^(-1)` product, if `(R )-2`-Chloro butane on reaction with `NaOH//H_(2)O` and acetone gives `98%` inverted product.

A

`4%`

B

`2%`

C

`6%`

D

`8%`

Text Solution

Verified by Experts

The correct Answer is:
A
Inversion `= 98%`, Retention `=2%`
`therefore` Inversion from `SN^(1) = 2%`
`therefore` Inversion from `SN^(2)=96%`
`therefore %SN^(1)=4`
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