Home
Class 12
CHEMISTRY
A 45 ml mixture of hydrogen and oxygen i...

A 45 ml mixture of hydrogen and oxygen is sparked to form liquid water. If reaction is taking place completely and `15 ml` gas is left over. The composition by volume in the original mixture of `H_(2):O_(2)` may be

A

`4:5`

B

`8:5`

C

`3:8`

D

`3:5`

Text Solution

Verified by Experts

The correct Answer is:
A
`2H_(2)+O_(2)rarr2H_(2)O`
`H_(2)` in excess 20:25
`O_(2)` in excess `35:10`
Promotional Banner

Similar Questions

Explore conceptually related problems

A mixture of 100 mL of oxygen and 500 mL of hydrogen is reacted to form water . What is maximum theoretical decrease in volume at 25^@C ?

30 ml of a mixture of oxygen (O_(2)) and ozone (O_(3)) was heated till ozone was completely decomposed. The mixture on cooling was found to expand 40 ml. The volume of O_(2) in original mixture was :

100 ml of mixture of CH_(4)(g), O_(2)(g) "and" CO_(2)(g) was sparked. There was contraction of 70 ml volume when the mixture was passed through aqueous KOH. The composition of initial gas mixture in (ml) will be in order of CH_(4)O_(2),CO_(2) :

20 ml of a gaseous mixture of N_2 and H_2 gases is mixed with 8 ml O_2 and the mixture is fired.if the final volume becomes 13 ml the volume percent of N_2 in the original mixture is :

40 ml of gaseous mixture of CO and ethyne is mixed with 100 ml of O_2 and burnt. The volume of gases after combustion is 105 ml. The composition of the original mixture is

When 20ml of mixture of O_(2) and O_(3) is heated the volume becomes 29ml and disappears in alkaline pyragallol solution. What is the volume precent of O_(2) in the originl mixture ? .

A mixture of 100ml of CO,CO_(2) and O_(2) was sparked. When the resulting gaseous mixture was passed through KOH solution, contraction in volume was found to be 80ml , the composition of initial mixture may be (in the same order)

The volume of oxygen liberated from 15 ml of 20 volume H_(2)O_(2) is