[3x=2x+18],[4z+3=6+2z]...

[3x=2x+18],[4z+3=6+2z]

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Find x ,\ y and z so that A=B , where A=[x-2 3 2z 18 z y+2 6z] , B=[y z6 6y x2y]

Find x,y,z such that A=B where A=[[x-2,3,2z],[18z,y+2,6z]] and B=[[y,z,6] , [6y,x,2y]]

The distance between the planes 3x + 2y - 6z - 18 = 0 and 3x + 2y - 6z + 10 = 0 is

The distance between the planes, 3x + 2y - 6z - 18 =0 and 3x+2y-6z+10=0 is,

The matrix form of the system of equations 2x-y+8z=13,3x+4y+5z=18 , 3x-2y-4z=-13 is

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