" (iv) "f(x)={[(1-cos kx)/(x sin x),,x!=0],[1/2,,x=0]

If f(x)={((1-cos kx)/(x sin x),x!=0),((1)/(2),x=0)} is continuous at x=0, find k,((1)/(2),x=0)}

The value of k(k f(x)= {((1-cos kx)/(x(sin x)),x!=0 or (1)/(2),x=0} ,is continous at x=0 is :

If f(x)={[(cos x)^((1)/(sin x)),,x!=0],[K,,x=0]} is differentiable at x=0 Then K=

If the function f(x) = {((1-cos kx)/(x sin x),x ne 0),((1)/(2), x = 0):} is continuous at x = 0, then the value (s) of k are:

The value of k (k lt 0) for which the function ? defined as f(x) ={((1-cos kx)/(x sin x),","x ne 0),((1)/(2),","x=0):} is continuous at ? = 0 is:

f(x)=(1-cos alpha x)/(x sin x), for x!=0,(1)/(2), for x=0 If f is continuous at x=0, then

If f(0) = 2 , and f(x) = (1-cos kx)/(x.sin x) , x != 0 , is continuous at x = 0 , then : k =

if f(x)=(1-cos ax)/(x sin x)" for "x ne 0, f(0)=1//2 is continuous at x=0 then a=

Find the values (s) of k so that the following function is continuous at x=0 f(x ) = {{:( (1- cos kx )/( x sin x ) , " if " x ne o),( 1/2, I f x=0):}