If the distance covered by a particle is given by the relation `x=at^(2)`. The particle is moving with : (where a is constant)

A particle of mass M is moving in a circular path of radius 2m. Its speed depends on the distance covered by the particle from the hegining according to the relation c = ks, where k is a positive constant and s is the distance covered. The power of force acting on teh particle when the particle has covered half of the circular path will be :

A particle with specific charge q//m moves rectilinerarly due to an electric field E = E_(0) - ax , where a is a positive constant, x is the distance from the point where the particle was initially at rest. Find: (a) the distance covered by the particle till the moment it came to a standstill, (b) the acceleration of the particle at that moment.

The displacement of a particle is given by x = (t-2)^(2) where x is in metre and t in second. The distance covered by the particle in first 4 seconds is

The displacement of a particle is given by x=(t-2)^(2) where x is in meters and in seconds. The distance covered by the particle in first 4 seconds is :

The displacement of a particle moving in a straight line is described by the relation s=6+12t-2t^(2) . Here s is in metre and t in second. The distance covered by the particle in first 5s is

The displacement of a particle moving in a straight line is described by the relation s=6+12t-2t^(2) . Here s is in metre and t in second. The distance covered by the particle in first 5s is

The displacement of a particle moving in a straight line is described by the relation s=6+12t-2t^(2) . Here s is in metre and t in second. The distance covered by the particle in first 5s is

A particle of mass m initially moving with speed v.A force acts on the particle f=kx where x is the distance travelled by the particle and k is constant. Find the speed of the particle when the work done by the force equals W.