The value of m where `2x+3y-z=5` and `3x-my+3z=6` are perpendicular with each other?

The value of m for which the planes 2x+3y-z=5 and 3x-my+3z=6 are perpendicular to each other is

The value of m for which the planes 2x + 3y -z = 5 and 3x - my + 3z =6 are perpendicular to each other is

The value of k for which the planes 3x-6y-2z=7 and 2x+y-kz=5 are perpendicular to each other is

The value of k for which the planes 3x-6y-2z=7 and 2x+y-kz=5 areperpendicular to each other is

Prove tht the normals to the planes 4x+11y+2z+3=0 and 3x-2y+5z=8 are perpendicular to each other.

Find the value of k for whicj the planes: 3x-6y-2z=7 and 2x+y-kz=5 are perpendicular to each other.

If the planes 2x - 4y + 3z = 5 and x + 2y + gamma z = 12 are perpendicular to each other, what is the value of lamda ?

Find the value of 'k' for which the plane : 3x - 6y - 2z = 7 and 2x + y - kz = 3 are perpendicular to each other.

Find the value of lambda for which the planes 2x-4y+3z=7 and x+2y+lambdaz=18 are perpendicular to each other.