If `v=(t^(2)-4t+10^(5))`m/s where t is in second. Find acceleration at t=1 sec.

The velocity of a particle is given by v=(4t^(2)-4t+5)m//s where t is time in seconds. Find its acceleration at t=4 second.

The velocity of a particle is given by v=(4t^(2)-4t+3)m//s where t is time in seconds. Find its acceleration at t=1 second.

The velocity of a particle is given by v=(5t^(2)-6t+5)m//s where t is time in seconds. Find its acceleration at t=4 second.

The velocity of a particle is given by v=(2t^(2)-4t+3)m//s where t is time in seconds. Find its acceleration at t=2 second.

The velocity of a particle is given by v=(2t^(2)-4t+3)m//s where t is time in seconds. Find its acceleration at t=2 second.

The velocity of a particle is given by v=(2t^(2)-4t+3)m//s where t is time in seconds. Find its acceleration at t=2 second.

The velocity of a particle is given by v=(5t^(2)-2t+9)m//s where t is time in seconds. Find its acceleration at t=4 second.

Block B has a downward velocity in m//s and given by v_(B)=t^(2)/2+t^(3)/6 , where t is in s. Acceleration of A at t=2 second is

[" If position of particle moving in straight line is "],[" given by "x=(t^(3)-2t+10)m" ,where t is time in "],[" second,then acceleration of particle at "t=1],[" sec is "......]

A particle moves in a circle of radius 2 cm at a speed given by v = 4t , where v is in cm s^-1 and t is in seconds. (a) Find the tangential acceleration at t = 1 s (b) Find total acceleration at t = 1 s .