0.1 " mol of "`MnO_(4)^(ɵ)` (in acidic medium) can:

In a redox reaction, how many moles of electrons are accepted by 1 mol of MnO_(4)^(-) in acidic medium ?

1 mole of ferric oxalate is oxidised by x mole of MnO_(4)^(-) in acidic medium, Hence value of x is:

1 mole of ferric oxalate is oxidised by x mole of MnO_(4)^(-) in acidic medium, Hence value of x is:

1 mole of ferric oxalate is oxidised by x mole of MnO_(4)^(-) in acidic medium, Hence value of x is:

1 mole of ferric oxalate [Fe_(2)(C_(2)O_(4))_(3)] is oxidised by "x" mole of MnO_(4)^(-) in strong basic medium and "1" mole of ferrous oxalate [FeC_(2)O_(4)] is oxidised by "y" mole of " MnO_(4)^(-) " in acidic medium.Ratio of "x/y" is-

The quantity of electricity requried to reduce 0.05 mol of MnO_(4)^(-) to Mn^(2+) in acidic medium would be

The quantity of electricity requried to reduce 0.05 mol of MnO_(4)^(-) to Mn^(2+) in acidic medium would be