[x+y+z=4],[2x-y+z=-1],[2+y-3z=-9]

x+y+z=4 2x-y+z=-1 2x+y-3z=-9

2x+y+z=1x-y+2z=-1,3x+2y-z=4

Solve by matrix method 2x +y +z=1 x-2y-z =3//2 3y-5z =9

Solve x-y+z=4 , x+y+z=2 , 2x+y-3z=0

The values of x, y, z for the equations x-y+z=1, 2x-y=1, 3x+3y-4z=2 are

Using matrices, solve the following system of equations for x,y and z. 3x-2y+3z=8 , 2x+y-z=1 , 4x-3y+2z=4

2x+y-z=1 x-y+z=2 3x+y-2z=-1

Value of [[x+y, z,z ],[x, y+z, x],[y, y, z+x]], where x ,y ,z are nonzero real number, is equal to x y z b. 2x y z c. 3x y z d. 4x y z