" If "y=3[x]+1=4[x-1]-10" and "(x+2y)=kt

If y=3[x]+1=4[x-1]-10, then find the value of [x+2y] .

If y=3x+1=4[x-1]-10 then find the value of [x+2y]

If x/4+y/3=10/24 and x/2+y=1 , then the value of (x+y) is

If 3^(4x)=(81)^(-1) and 10^(1/y)=0. 0001 , find the value of 2^(-x+4y)

If X+Y=[[2,-1],[1,3],[-3,2]] and X-2Y=[[-2,-1],[-3,-1],[4,-2]] find X and Y.

The solution of equations 3x+4y=10 and x-y=1 is :

Let A={1,2,3,...10} and R={(x, y) : x+2y=10, x, y in A} be a relation A. Then, R^(-1) =

Solve the following equaions for x and y log_(10)x+(1)/(2)log_(10)x+(1)/(4)log_(10)x+"...."=y " and " (1+3+5+"...."+(2y-1))/(4+7+10+"...."+(3y-1))=(20)/(7log_(10)x) .