" Mole fraction of a gas in water is "0.001" at STP,determine its Henry's law constant."

Mole fraction of a gas in water is 0.001 at STP, determine its Henry' law constant.

Solubility of a gas in water is 0.001 m at STP, determine its Henry's law constant.

Solubility of a gas in water is 0.001 m at STP, determine its Henry's law constant.

What is Henry's law constant?

Define Henry's Law constant ?

The units of Henry’s law constant are

Let gas (A) present in air is dissolved in 20 moles of water at 298K and 20 atm pressure. The mole fraction of gas (A) in air is 0.2 and the Henry's law constant for solubility of gas (A) in water at 298K is 1×10^5 atm.The number of mole of gas (A) dissolved in water will be

Let gas (A) present in air is dissolved in 20 moles of water at 298K and 20 atm pressure. The mole fraction of gas (A) in air is 0.2 and the Henry's law constant for solubility of gas (A) in water at 298K is 1×10^5atm.The number of mole of gas (A) dissolved in water will be

The solubility of H_2S gas in water at STP.195m .Calculate its Henry's law constant at STP