If f: R -> R such that f(x)=4^x/(4^x+2) ...

If `f: R -> R` such that `f(x)=4^x/(4^x+2)` for all `x in R` then (A) `f(x) =f(1-x)` (B) `f(x) +f(1-x) =0` (C) `f(x) +f(1-x) =1` (D) `f(x) +f(x-1) =1`

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