In `DeltaABC` we have `AB=5. BC=7, and AC=9.` Also, `D` is on `overline(AC)` with `BD=5.` What is `(AD)/(DC)` ?

In an isosceles triangleABC , If AB=AC and AD is the median, then overline(AD)*overline(BC)=

In DeltaABC , if AB=AC and BD=DC (see figure), then angleADC=

In Delta ABC, AB = AC and D is a point an side AC such that AD = BD = BC . Show that : angle ADB = 108 ^(@)

In a DeltaABC , AC = 12 cm, AB = 16 cm and AD is the bisector of angleA . If BD = 4 cm, then what is DC equal to ?

In Delta ABC, AB = AC and AD is the angle bisector hat(A) meeting BC at D. If BD = 2.5 cm. Find BC.

Let ABC be a right triangle with length of side AB=3 and hyotenus AC=5. If D is a point on BC such that (BD)/(DC)=(AB)/(AC), then AD is equal to

Let ABC be a right triangle with length of side AB=3 and hyotenus AC=5. If D is a point on BC such that (BD)/(DC)=(AB)/(AC), then AD is equal to