sin A+sin B-sin C=4sin(A)/(2)sin(B)/(2)cos(C)/(2)

If A+B+C=pi , prove that: "sin" A+"sin" B-"sin" C=4 "sin"(A)/(2)"sin"(B)/(2)"cos"(C)/(2) .

Theorem 4:sin A+sin B+sin C=4(cos A)/(2)(cos B)/(2)(cos C)/(2)

Assertion A:In/_ABC,sum(cos A)/(sin B sin C)=2 Reason R:In/_ABC,sin A+sin B+sin C=4(cos A)/(2)(cos B)/(2)(cos C)/(2)

If A+B+C=pi then prove that cos A+cos B+cos C=1+4sin((A)/(2))*sin((B)/(2))*sin((C)/(2))

If A , B , C are angles in a triangle , then prove that sin A + sin B + sin C =4 cos. (A)/(2) cos . (B)/(2) cos .(C)/(2)

sin A + sin B + sin C = 4cos ((A) / (2)) cos ((B) / (2)) cos ((C) / (2))

If A + B + C = 180^(@) , prove that sin A + sin B + sin C = 4 cos (A)/(2) cos"" (B)/(2) cos"" (C )/(2)

If A + B + C = pi , prove that cos A + cos B + cos C= 1 + 4 sin(A/2) sin(B/2) sin(C/2)

If A + B + C =pi , prove that : sin A + sin B -sin C = 4 sin frac (A)(2) sin frac (B)(2) cos frac (C)(2) .