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Find the General value of θ sintheta+sin...

Find the General value of θ `sintheta+sin2theta+sin3theta=1+costheta+cos2theta`

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(sintheta+sin2theta)/(1+costheta+cos2theta)

(sintheta+sin2theta)/(1+costheta+cos2theta)

costheta-cos2theta=sin3theta

(sintheta+sin2theta)/(1+costheta+cos2theta) =

(sintheta+sin2theta)/(1+costheta+cos2theta)=?

(sintheta+sin 2theta)/(1+costheta+cos2theta)=

(sin3theta-cos3theta)/(sintheta+costheta)+1 =

Prove that (sintheta +sin2theta)/(1+costheta +cos2theta)=tantheta

Evaluate : a Sin^3theta Costheta + a Sintheta Cos^3theta