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[" Find the radue of "sin[(pi)/(3)-sin^(...

[" Find the radue of "sin[(pi)/(3)-sin^(-1)[(-1)/(2)]" is equal "],[+9" .- "]

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sin[pi/2-sin^(-1)(-(1)/(2))] is equal to:

sin [(pi)/(3) - sin^(-1) (-(1)/(2))] is equal to :

Find the value of sin(pi/3-sin^(-1)(-1/2)) .

sin((pi)/(3)-sin^(-1)(-(1)/(2))) is equal to (A)

Evaluate sin[(pi)/(3) -sin^(-1)(-(1)/(2))]