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A swimmer coming out from a pool is cove...

A swimmer coming out from a pool is covered with a film of water weighing about 18 g. how much heat must be supplied to evaporate this water at 298 K ? Calculate the internal energy of vaperization at `100^(@)C`. `Delta_(vap)H^(Theta)` for water at 373 K = 40.66 kJ `mol^(-1)`

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A swimmer coming out from a pool is covered with a film of water weighing about 18g. How much heat must be supplied to evaporate this water at 298 K? Calculate the internal energy of vaporisation at 100^@C . DeltaH_(vap)^@ for water at 373K = 40.66 kJ mol^(-1)

A swimmer coming out from a pool is covered with a film of water weighing about 18g. How much heat must be supplied to evaporate this water at 298 K ? Calculate the internal energy of vaporisation at 298K. Delta_("vap")H^(Ө) for water at 298K =44.01 kJ "mol"^(-1)

A swimmer coming out from a pool is covered with a film of water weighing about 80g . How much heat must be supplied to evaporate this water ? If latent heat of evaporation for H_(2)O is 40.79 kJ mol^(-1) at 100^(@)C .

A swimmer coming out from a pool is covered with a film of water weighing about 80g . How much heat must be supplied to evaporate this water ? If latent heat of evaporation for H_(2)O is 40.79 kJ mol^(-1) at 100^(@)C .

A swimmer coming out from a pool is covered with a film of water weighing about 80g . How much heat must be supplied to evaporate this waateer ? If latent heat of evaporation for H_(2)O is 40.79 kJ mol^(-1) at 100^(@)C .

18g of water is taken to prepare the tea. Find out the internal energy of vaporisation at 100^(@) C. (Delta_(vap)H for water at 373 K is 40.66kJ mol^(-1))