The change in the enthalpy of `NaOH+HCl rarr NaCl+H_(2)O` is called :

Heat of neutralisation for the reaction NaOH + HCl rarr NaCl + H_(2)O " is " -57.1 kJ "mole"^(-1) . The heat relased when 0.25 moles of NaOH is treated with 0.25 moles of HCl is

In the equation X + HCl rarr NaCl + H_(2)S , what is X ?

Heat of neutralization of the reaction, NaOH+HCl rarr NaCl + H_(2)O is 57.2"kJ mol"^(-1) . What will be the heat released when 0.25 mole of NaOH is titrated against 0.25 mole of HCl

Balance the chemical equation : NaOH + HCl → NaCl + H2O

Identify the type of reaction NaOH + HCl to NaCl + H_2O

The enthalphy change for the reaction, H_2O(s)rarrH_2O_(l) is called enthalpy