What are the solution of the equation `log_x xy xx log_y xy + log_x(x-y)xxlog_y(x-y)=0`

Solve the system of equations log_2y=log_4(xy-2),log_9x^2+log_3(x-y)=1 .

Solve the system of equations log_2y=log_4(xy-2),log_9x^2+log_3(x-y)=1 .

Solve the system of equations log_2y=log_4(xy-2),log_9x^2+log_3(x-y)=1 .

If x and y satisfy the following system of equations, log x – log y = -2 , log x + 2 log y=1 then the value of xy is

The solution of x (dy)/(dx) + y log y = xy e^(x) is

Prove that log_(a)xy=log_(a)x+log_(a)y.