Ultraviolet light of wavelength 66.26 nm and intensity `2 W//m^(2)` falls on potassium surface by which photoelectrons are ejected out. If only 0.1% of the incident photons produce photoelectrons, and surface area of metal surface is `4 m^(2)`, how many electrons are emitted per second?

The work function of potassium is 2.2 eV. UV light of wavelength 3000 Å and intensity 2 Wm^(-2) is incident on the potassium surface. (i) Determine the maximum kinetic energy of the photo electrons (ii) If 40% of incident photons produce photo electrons, how many electrons are emitted per second if the area of the potassium surface is 2 cm^(2) ?

Ultraviolet light of wavelength 300nm and intensity 1.0Wm^-2 falls on the surface of a photosensitive material. If one per cent of the incident photons produce photoelectrons, then the number of photoelectrons emitted per second from an area of 1.0 cm^2 of the surface is nearly

Ultraviolet light of wavelength 300nn and intensity 1.0Wm^-2 falls on the surface of a photosensitive material. If one per cent of the incident photons produce photoelectrons, then the number of photoelectrons emitted per second from an area of 1.0 cm^2 of the surface is nearly

Ultraviolet light of wavelength 300nn and intensity 1.0Wm^-2 falls on the surface of a photosensitive material. If one per cent of the incident photons produce photoelectrons, then the number of photoelectrons emitted per second from an area of 1.0 cm^2 of the surface is nearly

Ultraviolet light of wavelength 350 nm and intensity 1 W//m^2 is directed at a potassium surface having work function 2.2 eV (ii) if 0.5 percent of the incident photons produce photoelectric effect, how many photoelectrons per second are emitted from the potassium surface that has an area 1 cm^2 . E_("kmax") =1.3 eV, n= 8.8 xx 10^(11)("photo electron")/("second") or r =(Nhv)/t =nhv

Light of wavelength 5000 Å and intensity of 3.96 xx 10^(-3) watt//cm^(2) is incident on the surface of photo metal . If 1% of the incident photons only emit photo electrons , then the number of electrons emitted per unit area per second from the surface will be

Light of wavelength 5000 Å and intensity of 3.96 xx 10^(-3) watt//cm^(2) is incident on the surface of photo metal . If 1% of the incident photons only emit photo electrons , then the number of electrons emitted per unit area per second from the surface will be