Solve `6 sin^2 theta - sin theta cos theta - cos^2 theta = 3.`

solve 6sin^(2)theta-sin theta cos theta-cos^(2)theta=3

Solve: sin 2 theta = cos 3 theta.

((cos theta - cos 3 theta ) ( sin 8 theta + sin 2 theta ))/(( sin 5 theta - sin theta )( cos 4 theta - cos 6 theta ))=

Solve : 3-2 cos theta -4 sin theta - cos 2theta+sin 2theta=0 .

Solve : 3-2 cos theta -4 sin theta - cos 2theta+sin 2theta=0 .

Solve : 3-2 cos theta -4 sin theta - cos 2theta+sin 2theta=0 .

The least value of cos^(2) theta - 6 sin theta.cos theta+ 3 sin^(2) theta+2 is

Show that ((cos theta - cos 3theta)(sin 8theta + sin 2 theta))/((sin 5 theta - sin theta)(cos 4 theta - cos 6 theta)) = 1