" (ii) "x+2y=5,3x+ay+15=0

x - y - 5 =0, 3x + 5y - 15 = 0

{:(x - 2y = 5),(3x - 6y = 15):}

Show that the lines : 3x-2y+5=0, y+3z-15=0 and (x-1)/5=(y+5)/-3=z/1 are perpendicular to each other.

The equation of the line passing through the point (x', y') and perpendicular to the line y y'=2a (x+x') is ................ A) x y'+2ay+ 2 ay' -x'y'=0 B) x y' +2ay-2ay' -x'y'=0 C) x y' +2ay+2ay' -x'y'=0 D) xy'+ 2ay-2ay' +x'y'=0

Orthocentre of the triangle formed by the lines xy-3x-5y+15=0 and 3x+5y=15 is

Orthocentre of the triangle formed by the lines xy-3x-5y+15=0 and 3x+5y=15 is

Orthocentre of the triangle formed by the lines xy-3x-5y+15=0 and 3x+5y=15 is