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int1/(9+16cos^2x)dx...

`int1/(9+16cos^2x)dx`

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int1/(1+cos^(2)x)dx=

int1/(1+cos^(2)x)dx=

int(1)/(9+16cos^(2)x)dx

Evaluate the following integrals: int1/(1-cos^2x)dx .

Evaluate: (i) int1/(1+cos2x)\ dx (ii) int1/(1-cos2x)\ dx

Evaluate: int1/(3+2cos^2x)\ dx

int(1)/(9+cos x)dx

int(1)/(16cos^(2)x+25sin^(2)x)dx

(i) int(1)/((1+cos2x))dx , (ii) int (1)/((1-cos2x)) dx

int1/(16+9x^(2))dx