A radiation of wavelength `lamda` illuminates a metal and ejects photoelectrons of maximum kinetic energy of 1eV. Aother radiation of wavelength `(lamda)/(3)`, ejects photoelectrons of maximum kinetic energy of 4eV. What will be the work function of metal?

A light source of wavelength lambda illuminates a metal and ejects photoelectron with (KE)^(max) = 1 eV. Another light source of wave length (lambda)/(3), ejects photoelectrons from same metal with (KE)^(max)=5 eV. Find the value of work function (eV) of metal.

A light source of wavelength lambda illuminates a metal and ejects photoelectron with (KE)^(max) = 1 eV. Another light source of wave length (lambda)/(3), ejects photoelectrons from same metal with (KE)^(max)=5 eV. Find the value of work function (eV) of metal.

A light source of wavelength lambda illuminates a metal and ejects photoelectron with (KE)^(max) = 1 eV. Another light source of wave length (lambda)/(3), ejects photoelectrons from same metal with (KE)^(max)=5 eV. Find the value of work function (eV) of metal.

Violet light is falling on a photosensitive material causing ejection of photoelectrons with maximum kinetic energy of 1 eV . Red light falling on metal will cause emission of photoelectrons with maximum kinetic energy (approximately) equal to

Violet light is falling on a photosensitive material causing ejection of photoelectrons with maximum kinetic energy of 1 eV . Red light falling on metal will cause emission of photoelectrons with maximum kinetic energy (approximately) equal to

When photons of wavelength lambda_(1) = 2920 Å strike the surface of metal A, the ejected photoelectron have maximum kinetic energy of k_(1) eV and the smallest de-Broglie wavelength of lambda . When photons of wavelength lambda_(2) = 2640 Å strike the surface of metal B the ejected photoelectrons have kinetic energy ranging from zero to k_(2) = (k_(1) – 1.5) eV . The smallest de-Broglie wavelength of electrons emitted from metal B is 2lambda . Find (a) Work functions of metal A and B. (b) k_(1) Take hc = 12410 eV Å

When photones of energy 4.0 eV fall on the surface of a metal A, the ejected photoelectrons have maximum kinetic energy T_(A) ( in eV) and a de-Broglie wavelength lambda_(A) . When the same photons fall on the surface of another metal B, the maximum kinetic energy of ejected photoelectrons is T_(B) = T_(A) -1.5eV . If the de-Broglie wavelength of these photoelectrons is lambda_(B) =2 lambda _(A) , then the work function of metal B is