`7^((log)_7x)+2x+9=0`

7^((log)_(7)x)+2x+9=0

Solve for x:backslash x^(2)+7^(log_(7)x)-2=0

Differentiate (log)_7((log)_7x) with respect to x :

Differentiate (log)_(7)((log)_(7)x) with respect to x

Sum of all the solutions of the equation 5^((log_(5)7)^(2x))=7^((log_(7)5)^(x)) is equal to

6-(1+4.9^(4)-2log_(7)3^(3))*log_(7)x=log_(x)7,x in Q

Find x, if : (i) log_(3) x = 0 (ii) log_(x) 2 = -1 (iii) log_(9) 243 = x (iv) log_(5) (x - 7) = 1 (v) log_(4) 32 = x - 4 (vi) log_(7) (2x^(2) - 1) = 2

The solution of the equation "log"_pi("log"_(2) ("log"_(7)x)) = 0 , is

The solution of the equation "log"_pi("log"_(2) ("log"_(7)x)) = 0 , is

(d)/(dx)log_(7)(log_(7)x)= (a) (1)/(x log_(e)x) (b) (log_(e)7)/(x log_(e)x) (c) (log_(7)e)/(x log_(e)x) (d) (log_(7)e)/(x log_(7)x)