(i) `tan3thetatan7theta+1=0` (ii) `sin^2theta=sin^2alpha`

If tan 2theta . Tan 3 theta =1 , then sin5theta =

If theta = 45^0 , then : (i) tan^2 theta + 1/(sin^2 theta) (ii) cos^2 theta - sin^2 theta

If tan theta=(tan alpha+tan beta)/(1+tan alpha tan beta) then show that sin2 theta=(sin2 alpha+sin2 beta)/(1+sin2 alpha sin2 beta)

[[1, -tan thetatan theta, 1]] [[1, -tan thetatan theta, 1]] ^ (- 1) = [[cos alpha, -sin alphasin alpha, cos alpha]]

If tan theta = ( tan alpha + tan beta)/(1 + tan alpha tan beta),"show that " sin 2 theta =(sin 2 alpha + sin 2 beta)/(1+sin 2 alpha sin 2 beta)

If tan(alpha+theta)=n tan(alpha-theta), show that (n+1)sin2 theta=(n-1)sin2 alpha.