The ratio of angles in a triangle `ABC` is `2:3:7` then prove that `a:b:c=sqrt2:2:(sqrt3+1)`

The ratio of the sides of a triangle ABC is 1:sqrt(3):2. The ratio A:B:C is

In a triangle ABC if 2a= sqrt(3)b+c then

The ratio of the sides of a triangle ABC is 1: sqrt3:2. Then the ratio A:B:C is-

The ratio of the sides of a triangle ABC is 1: sqrt3: 2 . The ratio A: B :C is

In triangle ABC if cosAcosB +sinAsinB sinC=1 then prove that a:b:c=1:1:sqrt2

The angles of a triangle ABC are in A.P. and it is being given that b:c= sqrt(3) : sqrt(2) , find angleA .

The angles of a triangle ABC are in A.P .and it is being given that b:c=sqrt(3):sqrt(2), find /_A.

In a triangle ABC, if A,B, C are in A.P and b:c = sqrt3:sqrt2 , then

The angles of a triangle ABC, are in Arithmetic progression and if b : c = sqrt(3) : sqrt(2), "find "angleA

The angles of a triangle ABC are in AP and if it is being given the b:c=sqrt3:sqrt2,"find"/_A, /_Band/_C.