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A=[[2,1],[4,1]]; B=[[3,4],[2,3]] & c=[[3...

`A=[[2,1],[4,1]]; B=[[3,4],[2,3]]` & `c=[[3,-4],[-2,3]]`, `tr(A)+tr[(ABC)/2]+tr[(A(BC)^2)/4]+tr[(A(BC)^2)/8]+.....oo` is:

Text Solution

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`A = [[2,1],[4,1]]`
`B = [[3,4],[2,3]]`
`C = [[3,-4],[-2,3]]`
`:. BC = [[3,4],[2,3]][[3,-4],[-2,3]] = [[9-8,-12+12],[6-6,-8+9]] = [[1,0],[1,0]] = I`
`:. (BC)^2 = (BC)^4 =... = I`
So, required expression becomes,
`tr(A) + tr[A/2]+tr[A/4]+...oo`
Now, `tr(A) = `Sum of diagonals `= 2+1 = 3`
...
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