Home
Class 11
MATHS
If the circles x^2+y^2+2x+2ky+6=0 and x^...

If the circles `x^2+y^2+2x+2ky+6=0` and `x^2+y^2+2ky+k=0` intersect orthogonally then k equals (A) `2 or -3/2` (B) `-2 or -3/2` (C) `2 or 3/2` (D) `-2 or 3/2`

Promotional Banner

Similar Questions

Explore conceptually related problems

If the circles x^2+y^2+2x+2ky + 6=0 and x^2+y^2+2ky+k=0 intersect orthogonally , then k is :

If the circles x^2+y^2+2x+2ky+6=0 and x^2+y^2+2ky+k=0 intersect orthogonally, show that k=2 or -3/2

If the circles x^2 + y^2 + 2x + 2ky + 6 = 0 and x^2 + y^2 + 2ky + k = 0 intersect orthogonally, then k is equal to _____

If the circles x^(2) + y^(2) + 2x + 2ky + 6 = 0 and x^(2) + y^(2) + 2ky + k = 0 intersect orthogonally , then k is equal to _