Calculate the volume percent of chlorine gas at equilibrium in the dissociation of `PCl_(5)(g)` under a total pressure of `1.5` atm. The `K_(p)` for its dissociation `=0.3`.

The volume percentage of Cl_2 at equilibrium in the dissociation of PCl_5 under a total pressure of 1.5atm is (Kp = 0.202) ,

The volume percentage of Cl_2 at equilibrium in the dissociation of PCl_5 under a total pressure of 1.5atm is (Kp = 0.202) ,

At a certain temperature, the degree of dissociation of PCI_(5) was found to be 0.25 under a total pressure of 15 atm. The value of K_(P) for the dissociation of PCl_(5) is

A certain temperature, the degree of dissociationof PCI_(3) was found to be 0.25 under a total pressure of 15 atm. The value of K_(p) for the dissociation of PCl_(5) is

Ata certain temperature, the degree of dissociationof PCI_(3) was found to be 0.25 under a total pressure of 15 atm. The value of K_(p) for the dissociation of PCl_(5) is

The degree of dissociation of PCl_(5) at 1 atm pressure is 0.2 . Calculate the pressure at which PCl_(5) is dissociated to 50% ?

The degree of dissociation of PCl_(5) at 1 atm pressure is 0.2 . Calculate the pressure at which PCl_(5) is dissociated to 50% ?

Assertion :- Adding inert gas at equilibrium to dissociation of PCl_(5) at constant pressure increases the degree of dissociation. Reason :- Since degree of dissociation x alphasqrt(v)